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X^2+10+2=2X+5
We move all terms to the left:
X^2+10+2-(2X+5)=0
We add all the numbers together, and all the variables
X^2-(2X+5)+12=0
We get rid of parentheses
X^2-2X-5+12=0
We add all the numbers together, and all the variables
X^2-2X+7=0
a = 1; b = -2; c = +7;
Δ = b2-4ac
Δ = -22-4·1·7
Δ = -24
Delta is less than zero, so there is no solution for the equation
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